Hi,
i am from germany. my english is not really good...but i try:
i created a slider with animate it. All ist good but the main problem is to run the animation after another in the SAME place/container.
if the first sliderimage is out then - but only then - the next sliderimage shoud start with the in-out-animation in the same container.
i solved it with long code (with a setinterval function and display:none) but i think it is a bad solution.
[edsanimate animation="bounceIn" delay="1" duration="1" infinite_animation="no" animate_on="" ]
<div id="div1"><img class="animated bounceOutLeft delay4" src="http://www.anywhere-anytime.de/wp-content/uploads/2015/10/s1-1280x540.png" alt="slider1- me" width="100%" />
</div>[i] // first slider-image in-out-animated[/i]
[/edsanimate]
[edsanimate animation="bounceIn" delay="9" duration="1" infinite_animation="no" animate_on="" ]
<div id="div2" style="display: none;">
<img class="animated bounceOutRight delay7" src="http://www.anywhere-anytime.de/wp-content/uploads/2015/10/s2-tablet.png" alt="slider1-me" width="100%" /></div>[i]// second slider-image in-out-animated[/i]
[/edsanimate]
[edsanimate animation="rotateIn" delay="9" duration="9" infinite_animation="no" animate_on="" ]
<div id="div3" style="display: none;"><img class="animated rotateIn delay1 duration1" src="http://www.anywhere-anytime.de/wp-content/uploads/2015/10/s3-sm.png" alt="slider3-me" width="100%" /></div>//third slider-image in-animated
[/edsanimate]
Jquery:
setTimeout(function(){ $("#div1").css("display","none"); }, 4000);
setTimeout(function(){ $("#div2").css("display","block"); }, 4000);
setTimeout(function(){ $("#div2").css("display","none"); }, 9000);
setTimeout(function(){ $("#div3").css("display","block"); }, 9000);
(result:
www.anywhere-anytime.de)
Any ideas for a shorter solution?